In young’s double slit expermint, the fringe width of a width light of wavelength 6000Å is 3 mm. the fringe width, when the wavelength of light is changed to 4000Å is :
Text Solution
Verified by ExpertsThe correct answer is:
C
Fringe width 
Where 
is the wavelength of light D is distance between slits and the screen d is distance between the two slits. As D and d remain the same 
Or 
Substituting the given values, we get
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